# How do you find the asymptotes for y = x/(x+3) ?

Jan 23, 2016

vertical asymptote at x = - 3 and horizontal asymptote at y = 1

#### Explanation:

Vertical asymptotes can be found when the denominator of a

rational function is 0 .

In this question when x + 3 = 0 hence x = - 3

[ Horizontal asymptotes can be found when the degree of the

numerator and the degree of the denominator are equal ]

Here they are both of degree 1 and so a horizontal asymptote
exists. The equation is found by taking the ratio of leading >coefficients

$\Rightarrow y = \frac{1}{1} = 1$

graph{x/(x+3) [-22.5, 22.5, -11.25, 11.25]}