Question

How do you find the asymptotes of `y = tan^-1(x-1) + pi/2`?

Answer 1

y = 0 and y = `pi`.

Explanation:

Inverse tangent varies from - `pi/2` to + `pi/2`. Correspondingly, (x - 1) varies from - infinity to + infinity and . y varies from 0 to `pi`
.(1, `pi/2`) is the center of this curve that extends to infinity in both +x and -x directions, tending to touch the asymptotes, y =0 and y = `pi`,. at infinity. . ,