Question

How do you find the average rate of change of `f(t)= t^2 -3` from [2,2.1]?

Answer 1

Use the definition: the average rate of change of `f` on `[a,b]` is `(f(b)-f(a))/(b-a`.

Explanation:

The average rate of change of `f(t)=t^2-1` on `[2,2.1]` is

`(f(2.1)-f(2))/(2.1-2) = ([(2.1)^2-3]-[(2)^2-3])/0.1`

`= (2.1^2-2^2)/0.1`

`= (4.41-4)/0.1`

`= 4.1`