How do you find the average rate of change of $f (x) = 5 x^{2}$ $f(x) = 5x^2$ from [4,4+h]?

Question

How do you find the average rate of change of $f (x) = 5 x^{2}$ $f(x) = 5x^2$ from [4,4+h]?

1 Answer

Impact of this question

3695 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-21T12:46:51

Average rate of change is $40 + 5 h$ $40+5h$

Explanation:

Given
$XXX f (x) = 5 x^{2}$ $color(white)("XXX")f(x)=5x^2$

Then
$XXX f (4) = 5 \times 4^{2}$ $color(white)("XXX")f(4)=5xx4^2$
$XXXXXX = 80$ $color(white)("XXXXXX")=80$
and
$XXX f (4 + h) = 5 \times {(4 + h)}^{2}$ $color(white)("XXX")f(4+h) = 5xx(4+h)^2$
$XXXXXXXX = 5 \times (16 + 8 h + h^{2})$ $color(white)("XXXXXXXX")=5xx(16+8h+h^2)$
$XXXXXXXX = 80 + 40 h + 5 h^{2}$ $color(white)("XXXXXXXX")=80+40h+5h^2$

Change between $f (4)$ $f(4)$ and $f (4 + h)$ $f(4+h)$
$XXX f (4 + h) - f (4)$ $color(white)("XXX")f(4+h) - f(4)$
$XXXXXXXXXXXX = 40 h + 5 h^{2}$ $color(white)("XXXXXXXXXXXX")=40h+5h^2$

This change occurs over an interval of $(4 + h) - (4) = h$ $(4+h) - (4) = h$

So the average rate of change is
$XXX \frac{40 h + 5 h^{2}}{h} = 40 + 5 h$ $color(white)("XXX")(40h+5h^2)/h = 40+5h$

Science

Math

Humanities

... and beyond

How do you find the average rate of change of $f (x) = 5 x^{2}$ $f(x) = 5x^2$ from [4,4+h]?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the average rate of change of f(x)=5x2f(x) = 5x^2 from [4,4+h]?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the average rate of change of $f (x) = 5 x^{2}$ $f(x) = 5x^2$ from [4,4+h]?