How do you find the average rate of change of #f(x)= x^3 -2x# over the interval [0,4]?
1 Answer
Jul 23, 2018
Explanation:
#"The average rate of change in the closed interval "[a,b]#
#"is a measure of the slope of the secant line joining the"#
#"points "(a,f(a))" and "(b,f(b))#
#"average rate of change "=(f(b)-f(a))/(b-a)#
#"here "[a,b]=[0,4]#
#f(b)=f(4)=4^3-8=56#
#f(a)=f(0)=0#
#"average rate of change "=(56-0)/4=14#
