Question

How do you find the average rate of change of the function `h(x) =sqrtx` over the given interval [16,49]?

Answer 1

`(h(49)-h(16))/(49-16) = 1/11`

Explanation:

`(h(49)-h(16))/(49-16) = (sqrt(49)-sqrt(16))/(49-16)`

`= (7-4)/33 = 3/33 = 1/11`