How do you find the average rate of change of #y=x^2+6x+10# over [1,3]?
1 Answer
Dec 8, 2016
Explanation:
Given:
#f(x) = x^2+6x+10#
The average rate of change of
#(Delta f(x))/(Delta x) = (f(b)-f(a))/(b-a)#
In other words, it is the slope of the chord joining
In our example, we find:
#f(1) = 1^2+6(1)+10 = 17#
#f(3) = 3^2+6(3)+10 = 37#
So the average rate of change of
#(Delta f(x))/(Delta x) = (f(3)-f(1))/(3-1) = (37-17)/2 = 20/2 = 10#