How do you find the average value of the function for #f(x)=2-1/2x, 0<=x<=4#?
2 Answers
Mar 22, 2018
The average value of the function on the given interval is
Explanation:
Average value of a function is given by
#A = 1/(b - a) int_a^b f(x) dx#
#A = 1/4 int_0^4 2 - 1/2x dx#
#A = 1/4[2x - 1/4x^2]_0^4#
#A = 1/4(2(4) - 1/4(4)^2)#
#A = 1/4(8 - 4)#
#A = 1/4(4)#
#A = 1#
Hopefully this helps!
Mar 22, 2018
The average value of
Explanation:
The average value of a function over an interval is its (definite) integral over that interval divided by the length of the interval.
#= 4 - 0 #
#= 4#
The average value of