# How do you find the center and radius of the circle #(3x-1)^2 + (3y+3)^2 = -1#?

##### 1 Answer

Jun 11, 2016

This equation has no solutions in Real coordinates

#### Explanation:

Note that if

#(3x-1)^2 >= 0#

#(3y+3)^2 >= 0#

So

Since the equation has no solution, it defines an empty set of points, not a circle.