# How do you find the center and radius of the circle given #x^2+y^2+4x-8=0#?

##### 1 Answer

Oct 22, 2016

we have the centre as:

radius

#### Explanation:

The standard equation of a circle is

where

we thus have to complete the square on the given equation.

rearrange slightly

comparing with

we have the centre as:

radius

graph{x^2+y^2+4x-8=0 [-10, 10, -5, 5]}