# How do you find the center and radius of the circle given (x-3)^2+(y-1)^2=25?

Nov 8, 2016

#### Answer:

centre is $\left(3 , 1\right)$

$r = 5$

#### Explanation:

the standard equation of a circle is

(x-a)^2+(y-b)^"=r^2

where $\left(a , b\right)$ is the centre of the circle

and $r$ its radius.

${\left(x - 3\right)}^{2} + {\left(y - 1\right)}^{2} = 25$

its centre is $\left(3 , 1\right)$

$r = \sqrt{25} = 5$