How do you find the center and radius of the circle given #(x-3)^2+(y-1)^2=25#?

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Answer 1 · 2016-11-08T21:57:20

centre is #(3,1)#

#r=5#

the standard equation of a circle is

#(x-a)^2+(y-b)^"=r^2#

where #(a, b) # is the centre of the circle

and #r# its radius.

#(x-3)^2+(y-1)^2=25#

its centre is #(3,1)#

#r=sqrt25=5#