# How do you find the center and radius of the circle given #(x-3)^2+y^2=16#?

##### 1 Answer

Oct 20, 2016

#(3, 0)#

Radius

#### Explanation:

Given -

#(x-3)^2+y^2=16#

The equation of the circle with center

#(x-h)^2+(y-k)^2=a^2#

In our case to find the center, rewrite the equation like this-

#(x-3)^2+(y-0)^2=16#

Then the center is -

#(3, 0)#

The radius is