# How do you find the center and radius of the circle #x^2-12x+y^2+4y+15=0#?

##### 1 Answer

Dec 18, 2016

The center is

#### Explanation:

We complete the squares and rearrange the equation

And now we factorise

We compare this equation to the standard equation of a circle

The centre is

In our case,

The center is

graph{x^2-12x+y^2+4y+15=0 [-6.22, 16.275, -6.95, 4.3]}