# How do you find the center and radius of the circle (x - 3) ^2 + (y + 1) ^2 = 9?

Feb 5, 2016

Center $\left(3 , - 1\right)$
$r a \mathrm{di} u s = 3$
The centre-radius form of a circle is ${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$ with the centre being $\left(h , k\right)$ and $r$ as the radius.
Given this, we would know that the center of the circle is $\left(3 , - 1\right)$ and the radius is 3.