# How do you find the center and radius of the circle: (x - 6)^2 + y^2 = 49?

Dec 2, 2015

Slightly reformulate in standard form to find that the centre is at $\left(6 , 0\right)$ and radius $7$.

#### Explanation:

This equation is essentially the same as:

${\left(x - 6\right)}^{2} + {\left(y - 0\right)}^{2} = {7}^{2}$

which is in the standard form:

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

... the equation of a circle with centre $\left(h , k\right)$ and radius $r$.

So the centre of our example circle is $\left(6 , 0\right)$ and radius $7$.