Question

How do you find the center and radius of the circle: `(x-7)^2+(y+2)^2=25`?

Answer 1

I found: center at `(7,-2)` and radius `r=5`.

Explanation:

Consider the general form of the equation of the circle:
`(x-h)^2+(y-k)^2=r^2`
with radius `r` and center at `(h,k)` in your case gives you:
`r=sqrt(25)=5`
`h=7`
`k=-2`