# How do you find the center and radius of X^2 + Y^2 = 13?

Feb 4, 2016

The center is (0,0) and the radius is $\sqrt{13}$

#### Explanation:

The equations of the circle is
${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$
where h is the x of the center of the circle and k is the y of the center of the circle, and r is the radius.

${\left(x\right)}^{2} + {\left(y\right)}^{2} = 13$
is
${\left(x - 0\right)}^{2} + {\left(y - 0\right)}^{2} = 13$

(2,6) radus is 3

h = 0
k = 0
r = $\sqrt{13}$
(0,0) radus is $\sqrt{13}$