# How do you find the center and radius of # (x+3)^2 +y^2 = 37#?

##### 2 Answers

Feb 3, 2016

I found: center at

#### Explanation:

We can compare our equation with the general equation of a circle with center at

giving us:

Feb 3, 2016

centre (-3 , 0 ) , radius =

#sqrt37 #

#### Explanation:

the standard form of the equation of a circle is

# (x-a)^2 + (y-b)^2 = r^2 # where centre = (a , b ) and r = radius.

the equation here is in this form and so values of a , b and r

can be written down.here a = -3 , b = 0 and

# r^2 = 37 rArr r = sqrt37 # hence centre = (-3 , 0 )