How do you find the center and radius of #( x - 3 )^ 2 + y ^2 = 4#?

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Answer 1 · 2016-12-02T10:50:38

The center is #(3,0)# and the radius #=2#

The equation of a circle is

#(x-a)^2+(y-b)^2=r^2#

The center is #(a,b)# and the radius #r#

We compare this to your equation

#(x-3)^2+(y-0)^2=2^2#

So,

The center is #(3,0)# and the radius #=2#

graph{(x-3)^2+(y)^2=4 [-6.24, 6.244, -3.12, 3.12]}