# How do you find the center and radius of #(X-5)^2 + Y^2 = 1/16#?

##### 1 Answer

Sep 17, 2016

#### Answer:

Centre at

#### Explanation:

The equation of a circle with centre at point

Here we are given the equation:

Hence, in this example:

Therefore the centre of the circle is at

The radius is

This can be seen on the graph of the positive portion of the circle below.

graph{(1/16 - (x-5)^2)^(1/2) [4.6156, 5.355, -0.057, 0.3128]}