How do you find the center and radius of #(x - 5) ^2 + (y + 3)^ 2 = 25#?
centre = (5 ,-3) and radius = 5
The standard form of the equation of a circle is.
where (a ,b) are the coordinates of the centre and r, the radius.
#(x-5)^2+(y+3)^2=25" is in this form"#
and by comparison with the standard form.
#a=5,b=-3" and " r^2=25rArrr=sqrt25=5#
Hence centre = (5 ,-3) and radius = 5