How do you find the center and vertex for #9x^2 – y^2 – 36x + 4y + 23 = 0#?
vertices would be (1,2) and (3,2)
First, we can complete the squares of x and y, by writing it as follows:
This equation represents a hyperbola with its center at (2,2). Its vertices would be (1,2) and (3,2)