# How do you find the center, foci and vertices of #(x-6)^2/4+(y+7)^2/16=1#?

##### 1 Answer

Dec 20, 2016

The center is

The foci are

The vertices are

#### Explanation:

The equation represents an ellipse.

with the major axis vertical

The general equation is

The center of the ellipse is

Let's calculate

The foci are F

and F'

The vertices are

A

A'

B

and B'

graph{(x-6)^2/4+(y+7)^2/16=1 [-10.13, 15.18, -11.41, 1.25]}