# How do you find the center (h,k) and radius r of the circle with the given equation x^2+(y-3)^2=16?

Dec 13, 2015

Center: $\left(0 , 3\right)$

Radius: $r = 4$

#### Explanation:

Standard form of a circle ${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$
Center : $\left(h , k\right)$
Radius : $r = \sqrt{{r}^{2}}$

Given ${x}^{2} + {\left(y - 3\right)}^{2} = 16$

Or can be written as " (x-0)^2 + (y-(3))^2 = 4^4

Center: $\left(0 , 3\right)$