# How do you find the center of the circle whose diameter has the endpoints P(7,2) Q(6,10)?

$\left(\frac{13}{2} , 6\right)$
centre =$\left[\frac{1}{2} \left(7 + 6\right) , \frac{1}{2} \left(2 + 10\right)\right] = \left(\frac{13}{2} , 6\right)$