Question

How do you find the center of the circle whose equation is `(x + 1)² + (y + 2)² = 49`?

Answer 1

centre = (-1 , -2 ) and r = 7

Explanation:

The standard form of the equation of a circle is

`(x-a)^2 + (y-b)^2 = r^2 " (a , b) is centre and r , the radius"`

`(x+1)^2 + (y+2)^2 = 49 " is in this form "`

by comparison : a= -1 , b=-2 and r = 7

hence centre = (-1 , -2 ) and r = 7