How do you find the center of the radius of #(x-4)^2 +y^2 =16#?

1 Answer
Jun 2, 2016

Answer:

Center: (4,0)

Radius=4

Explanation:

The circle formula is

#(x-x_1)^2+(y-y_1)^2=r^2#

The center of all circles is #(x_1,y_1)#, without the negative. The radius is the r. So we must square root the #r^2# to find r, and it will be the positive square root as length must be positive.

So from the equation

#(x-4)^2+(y^2)=16#

We can know the radius is #+sqrt16=4#

The center is #x_1, y_1#. #x_1=4# and #y_1=0#.

#y_1# is 0 as there must be a y co-ordinate of the center and the only number which allows #(y-y_1)^2=y^2# is 0