How do you find the center, radius, and the x-and y-intercepts of the following circle y^2+ x^2-12y +10x 57=0?

Apr 28, 2018

With a radius of 2 it will not touch either axis

Explanation:

I assume you have missed a sign from in front of the 57. I'll guess it's +57, just change it if not.

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$ is the general formula for a circle where $\left(a , b\right)$ are the cords of the centre and $r$ is the radius

Rearrange and complete the square

${\left(x + 5\right)}^{2} - 25 + {\left(y - 6\right)}^{2} - 36 = - 57$

${\left(x + 5\right)}^{2} + {\left(y - 6\right)}^{2} - 61 = - 57$

${\left(x + 5\right)}^{2} + {\left(y - 6\right)}^{2} = 4$