# How do you find the center, radius, and the x-and y-intercepts of the following circle #y^2+ x^2-12y +10x 57=0#?

##### 1 Answer

Apr 28, 2018

#### Answer:

Centre (-5,6) radius 2

With a radius of 2 it will not touch either axis

#### Explanation:

I assume you have missed a sign from in front of the 57. I'll guess it's +57, just change it if not.

Rearrange and complete the square

Centre (-5,6) radius 2

With a radius of 2 it will not touch either axis