How do you find the center-radius form of the equation of the circle given Center (0,-2), radius 6?

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Answer 1 · 2016-05-23T23:01:45

$(x-0)^2+(y-(-2))^2=6^2$

The center-radius form of the equation of a circle is:

$(x-h)^2+(y-k)^2 = r^2$

where $(h, k)$ is the center and $r$ the radius.

So in our example, we can write:

$(x-0)^2+(y-(-2))^2=6^2$

If we are slightly less fussy about the form, this simplifies to:

$x^2+(y+2)^2 = 36$