How do you find the center-radius form of the equation of the circle given Center (0,-2), radius 6?
1 Answer
May 23, 2016
Explanation:
The center-radius form of the equation of a circle is:
(x-h)^2+(y-k)^2 = r^2
where
So in our example, we can write:
(x-0)^2+(y-(-2))^2=6^2
If we are slightly less fussy about the form, this simplifies to:
x^2+(y+2)^2 = 36