# How do you find the center-radius form of the equation of the circle given Center (0,-2), radius 6?

##### 1 Answer

May 23, 2016

#### Explanation:

The center-radius form of the equation of a circle is:

#(x-h)^2+(y-k)^2 = r^2#

where

So in our example, we can write:

#(x-0)^2+(y-(-2))^2=6^2#

If we are slightly less fussy about the form, this simplifies to:

#x^2+(y+2)^2 = 36#