# How do you find the center, vertices, and foci of an ellipse (x+3)^2/225 + (y+8)^2/81 = 1?

Jan 19, 2016

Explained below

#### Explanation:

Center is (-3, -8).

Length of the semi major axis is 15, therefore vertices would be (-18,-8) and (12, -8).

Distance of the focus from the center is c= $\sqrt{{a}^{2} - {b}^{2}}$

= $\sqrt{225 - 81} = \sqrt{144} = 12$

Hence focii would be (-15, -8) and (9, -8)