# How do you find the center, vertices, foci and asymptotes of #(x^2/16)-(y^2/9)=1#?

##### 1 Answer

May 1, 2018

**Center** **Vertices are**

**Foci are** **and equation of
asymptotes are**

#### Explanation:

This is standard form of the equation of a hyperbola with center

The vertices are

Foci are

vertices of a rectangle of dimensions

centre at

asymptotes are is

graph{x^2/16-y^2/9=1 [-10, 10, -5, 5]} [Ans]