# How do you find the center, vertices, foci and eccentricity of #x^2/4+y^2/9=1#?

##### 1 Answer

**Foci**:

**Vertices**:

**Co-vertices**:

**Ecentricity**:

#### Explanation:

General formula for vertical ellipse

Remember:

Center:

Vertices

Eccentricity:

**Given:**

**Let's identify the center** :

#b^2 = 4; " "color(red)( b= 2) " " " " # # a^2 = 9; " "color(red)( a= 3) #

**Solve for**

#c^2 = 9-4 +> c^2 = 5 => color(red)(c= +-sqrt(5)#

Use the equation provided above, and "plug it" in

**Foci**:

**Vertices**:

**Co-vertices**:

**Ecentricity**: