# How do you find the center, vertices, foci and eccentricity of #x^2+4y^2+4x+32y+67=0#?

##### 1 Answer

Mar 2, 2016

Ellipse. C: (

#### Explanation:

Rearranging to the standard form ( x

The rearranged form is

( x + 2 )^2 + ( y + 4 )^2/(1/4) = 1

This represents an ellipse with axes parallel to axes of coordinates.

Center is (