How do you find the complex roots of #a^2-81=0#?
1 Answer
Nov 27, 2016
This quadratic has only two Real roots.
Explanation:
This can be factored as a difference of squares, or
#a^2-81=0#
#a^2-9^2=0#
#(a+9)(a-9)=0#
So the two solutions, both of which are Real, are