How do you find the complex roots of #t^3+2t^2-4t-8=0#?
1 Answer
Nov 26, 2016
The roots are:
#-2, -2, 2#
Explanation:
#0 = t^3+2t^2-4t-8#
#color(white)(0) = (t^3+2t^2)-(4t+8)#
#color(white)(0) = t^2(t+2)-4(t+2)#
#color(white)(0) = (t^2-4)(t+2)#
#color(white)(0) = (t^2-2^2)(t+2)#
#color(white)(0) = (t-2)(t+2)(t+2)#
So the roots are:
#-2, -2, 2#
There are no non-Real Complex roots.
