# How do you find the coordinates of the center, foci, the length of the major and minor axis given #(x+8)^2/144+(y-2)^2/81=1#?

##### 1 Answer

May 18, 2017

See the answer below

#### Explanation:

We compare this equation to the standard equation of a horizontal ellipse

The center of the ellipse is

The length of the major axis is

The length of the major axis is

We need

The foci are

graph{((x+8)^2/144+(y-2)^2/81-1)((x+8)^2+(y-2)^2-0.1)=0 [-26.1, 5.95, -5.07, 10.95]}