# How do you find the coordinates of the center for the given ellipse #4x^2+16x+352+16y^2+160y=0#?

##### 1 Answer

Dec 23, 2015

#### Answer:

#### Explanation:

Rearrange:

Complete the square after factoring out the coefficient on the squared terms.

This is in the standard form of an ellipse:

Where the ellipse has a center at

The trick to finding the center is remembering to switch the sign of whatever's inside the parentheses:

graph{(4x^2+16x)+(16y^2+160y)=-352 [-11.25, 8.75, -8.04, 1.96]}