How do you find the coordinates of the center of a circle whose equation is #(x+11)^2 +(y-13)^2=4#?
centre = (-11 , 13 )
The standard form of the equation of a circle is
# (x-a)^2 + (y-b)^2 = r^2 #
where (a , b ) are the coords of the centre and r , the radius.
The equation here is
# (x+11)^2 + (y-13 )^2#
By comparison with the standard form : centre = (-11 , 13)