# How do you find the coordinates of the center of a circle whose equation is #(x+11)^2 +(y-13)^2=4#?

##### 1 Answer

Feb 4, 2016

centre = (-11 , 13 )

#### Explanation:

The standard form of the equation of a circle is

# (x-a)^2 + (y-b)^2 = r^2 # where (a , b ) are the coords of the centre and r , the radius.

The equation here is

# (x+11)^2 + (y-13 )^2# By comparison with the standard form : centre = (-11 , 13)