# How do you find the coordinates of the center of a circle whose equation is (x+11)^2 +(y-13)^2=4?

##### 1 Answer
Feb 4, 2016

centre = (-11 , 13 )

#### Explanation:

The standard form of the equation of a circle is

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$

where (a , b ) are the coords of the centre and r , the radius.

The equation here is ${\left(x + 11\right)}^{2} + {\left(y - 13\right)}^{2}$

By comparison with the standard form : centre = (-11 , 13)