# How do you find the coordinates of the terminal points corresponding to the following arc length on the unit circle: -2π/3?

$x = \cos \left(\frac{- 2 \pi}{3}\right) = - \cos \left(\frac{\pi}{3}\right) = - \frac{1}{2}$
$y = \sin \left(\frac{- 2 \pi}{3}\right) = - \sin \left(\frac{\pi}{3}\right) = \frac{- s q r 3}{2}$