How do you find the coordinates of the terminal points corresponding to the following arc length on the unit circle: 11π/6?

1 Answer
Jun 4, 2015

Part 1: If you are okay with $11 \frac{\pi}{6} = - \frac{\pi}{6}$ go to Part 2.

Part 2: If you are okay with standard side lengths of triangles with angles $\frac{\pi}{3}$ and $\frac{\pi}{6}$, go to Part 3.

Part 3:

Coordinates of the required terminal point are
$\left(x , y\right) = \left(\frac{\sqrt{3}}{2} , - \frac{1}{2}\right)$