# How do you find the coordinates of the terminal points corresponding to the following arc length on the unit circle: -9π/-4?

$\left(\frac{\sqrt{2}}{2} , \frac{\sqrt{2}}{2}\right)$
Arc: $\frac{- 9 \pi}{-} 4 = \frac{9 \pi}{4} = \frac{\pi}{4} + \frac{8 \pi}{4} = \frac{\pi}{4} + 2 \pi$
$x = \cos \left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}$
$y = \sin \left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}$