# How do you find the critical points for #f(x) = x^3 - 15x^2 + 4# and the local max and min?

##### 1 Answer

Dec 21, 2016

#### Answer:

The critical points are:

#### Explanation:

To identify the critical points, we have to solve the equation:

that is:

so that the critical points for

We can now calculate the second derivative:

and note that around

graph{x^3-15x^2+4 [-80, 80, -640, 640]}