Question

How do you find the critical points to graph `f(x) = 4 sin(x - pi/2 ) + 1`?

Answer 1

0 and 2`pi` in the interval `(0, 2pi]`

Explanation:

`f' (x)= 4 cos (x-pi/2)`
At critical points f'(x)=0, that gives `cos(x-pi/2)=0`

`x-pi/2 =pi/2 , (3pi)/2`
`x= pi , 2pi` in the interval `(0,2pi]`