# How do you find the critical points to graph y = 3 sin (2x-2)?

Jul 1, 2018

As below.

#### Explanation:

Standard form of the sine function is
$y = A \sin \left(B x - C\right) + D$

$y = 3 \sin \left(2 x - 2\right)$

$A = 3 , B = 2 , C = 2 , D = 0$

$A m p l i t u \mathrm{de} = | A | = 3$

Period $= \frac{2 \pi}{|} B | = \frac{2 \pi}{2} = \pi$

Phase Shift $= - \frac{C}{B} = - \frac{2}{2} = - 1$, 1 to the LEFT

Vertical Shift $= D = 0$