Question

How do you find the definite integral of `int ((x^2)-4x+2)dx` from `[1,4]`?

Answer 1

`int_1^4(x^2-4x+2)dx=-3`

Explanation:

`int_1^4(x^2-4x+2)dx=[x^3/3-4x^2/2+2x]_1^4`

`=(4^3/3-2*4^2+2*4)-(1/3-2+2)`

`=-3`