How do you find the definite integral of #sqrt(y+1)*dy# from #[-1, 0]#? Calculus Introduction to Integration Formal Definition of the Definite Integral 1 Answer Eddie Jul 5, 2016 #= 2/3# Explanation: #int_{-1)^0 dy qquad sqrt(y+1)# this is simply the power rule ie #int du qquad u^n = n^{n+1}/(n+1)# So #=[2/3 (y+1)^(3/2)]_{-1)^0# #=[2/3 (0+1)^(3/2)] - [2/3 (-1+1)^(3/2)] = 2/3# Answer link Related questions What is the Formal Definition of the Definite Integral of the function #y=f(x)# over the... How do you use the definition of the definite integral? What is the integral of dy/dx? What is an improper integral? How do you calculate the double integral of #(xcos(x+y))dr# where r is the region: 0 less than... How do you apply the evaluation theorem to evaluate the integral #3t dt# over the interval [0,3]? What is the difference between an antiderivative and an integral? How do you integrate #3x^2-5x+9# from 0 to 7? Question #f27d5 How do you evaluate the definite integral #int sqrtt ln(t)dt# from 2 to 1? See all questions in Formal Definition of the Definite Integral Impact of this question 3654 views around the world You can reuse this answer Creative Commons License