# How do you find the definite integrals for the lengths of the curves, but do not evaluate the integrals for #y=x^3, 0<=x<=1#?

##### 1 Answer

Mar 14, 2018

#### Explanation:

Recall that the arc length of a curve is given by

#A = int_a^b sqrt(1 + (dy/dx)^2)dx#

Here this would be

#A = int_0^1 sqrt(1 + (3x^2)^2)dx#

#A = int_0^1 sqrt(1 + 9x^4)dx#

Hopefully this helps!