How do you find the derivative for #2x^4-1#? Calculus Basic Differentiation Rules Summary of Differentiation Rules 1 Answer Shura Jun 2, 2015 #f(x) = 2x^4 - 1 = g(x) + h(x)#, where #g(x) = 2x^4# and #h(x) = -1# #f'(x) = g'(x) + h'(x) = (2x^4)' + (-1)' = 4*2x^(4-1) + 0 = 8x^3#. Answer link Related questions What is a summary of Differentiation Rules? What are the first three derivatives of #(xcos(x)-sin(x))/(x^2)#? How do you find the derivative of #(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))#? How do I find the derivative of #y= x arctan (2x) - (ln (1+4x^2))/4#? How do you find the derivative of #y = s/3 + 5s#? What is the second derivative of #(f * g)(x)# if f and g are functions such that #f'(x)=g(x)#... How do you calculate the derivative for #g(t)= 7/sqrtt#? Can you use a calculator to differentiate #f(x) = 3x^2 + 12#? What is the derivative of #ln(x)+ 3 ln(x) + 5/7x +(2/x)#? How do you find the formula for the derivative of #1/x#? See all questions in Summary of Differentiation Rules Impact of this question 3186 views around the world You can reuse this answer Creative Commons License