Question

How do you find the derivative for `d/dx (2x+1)/(x^2-1)`?

Answer 1

`dy/dx =( [(x^2 - 1) (2)] - [(2x + 1) (2x)])/(x^2 - 1)`

`dy/dx =( [2x^2 - 2] - [4x^2 + 2x]) /(x^2 - 1)`
`dy/dx =( 2x^2 - 2 - 4x^2 - 2x) /(x^2 - 1)`
`dy/dx =( - 2x^2 - 2x - 2) /(x^2 - 1)`