# How do you find the derivative for d/dx (2x+1)/(x^2-1)?

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{\left[\left({x}^{2} - 1\right) \left(2\right)\right] - \left[\left(2 x + 1\right) \left(2 x\right)\right]}{{x}^{2} - 1}$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{\left[2 {x}^{2} - 2\right] - \left[4 {x}^{2} + 2 x\right]}{{x}^{2} - 1}$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{2 {x}^{2} - 2 - 4 {x}^{2} - 2 x}{{x}^{2} - 1}$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{- 2 {x}^{2} - 2 x - 2}{{x}^{2} - 1}$