# How do you find the derivative for (x^4 + 3x^2)/(x^2)?

##### 2 Answers
Jun 10, 2018

$f ' \left(x\right) = 2 x$

#### Explanation:

Writing your term in the form

$\frac{{x}^{4} + 3 {x}^{2}}{x} ^ 2 = {x}^{4} / {x}^{2} + 3 {x}^{2} / {x}^{2} = {x}^{2} + 3$
we get

$f ' \left(x\right) = 2 x$

Jun 10, 2018

$2 x$

#### Explanation:

$\frac{{x}^{4} + 3 {x}^{2}}{x} ^ 2 = {x}^{4} / {x}^{2} + \frac{3 {x}^{2}}{x} ^ 2 = {x}^{2} + 3$

$\frac{d}{\mathrm{dx}} \left({x}^{2} + 3\right) = 2 x$